|Published (Last):||12 June 2015|
|PDF File Size:||4.10 Mb|
|ePub File Size:||11.68 Mb|
|Price:||Free* [*Free Regsitration Required]|
You need a minimum of 11 pins to interface ADC, eight for data pins and 3 for control pins. As shown in the typical circuit the chip select pin can be made low if you are not using the microcontroller port for any other peripheral multiplexing. All you need is the datasheet of the IC you are working with and take a look at the timing diagram of the IC which shows how to send the data, which signal to assert and at what time the signal should be made high or low etc.
Note: Keep this in mind that whenever you are working with an IC and you want to know how to communicate with that IC, then simply look into the timing diagram of that IC from its datasheet. It gives you complete information that you need regarding the communication of IC. Also you can see which signals are to be asserted and at what time to start a conversion. We note down the steps or say the order in which signals are to be asserted to start a conversion of ADC.
As we have decided to make Chip select pin as low so we need not to bother about the CS signal in the timing diagram. Below steps are for starting an ADC conversion. I am also including CS signal to give you a clear picture. While programming we will not use this signal. Make chip select CS signal low. Make write WR signal low. Make chip select CS high. Wait for INTR pin to go low means conversion ends.
Below are the stepts to read output from the ADC Make chip select CS pin low. Make read RD signal low. Read the data from port where ADC is connected. Make read RD signal high.
PDF ADC0804 Datasheet ( Hoja de datos )
ADC0804 – CMOS 8-bit A/D Converter – Intersil